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8h^2+9h-575=0
a = 8; b = 9; c = -575;
Δ = b2-4ac
Δ = 92-4·8·(-575)
Δ = 18481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{18481}}{2*8}=\frac{-9-\sqrt{18481}}{16} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{18481}}{2*8}=\frac{-9+\sqrt{18481}}{16} $
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